CF1903F.Babysitting

Theofanis wants to play video games, however he should also take care of his sister. Since Theofanis is a CS major, he found a way to do both. He will install some cameras in his house in order to make sure his sister is okay.

His house is an undirected graph with $n$ nodes and $m$ edges. His sister likes to play at the edges of the graph, so he has to install a camera to at least one endpoint of every edge of the graph. Theofanis wants to find a vertex cover that maximizes the minimum difference between indices of the chosen nodes.

More formally, let $a_1, a_2, \ldots, a_k$ be a vertex cover of the graph. Let the minimum difference between indices of the chosen nodes be the minimum $\lvert a_i - a_j \rvert$ (where $i \neq j$ ) out of the nodes that you chose. If $k = 1$ then we assume that the minimum difference between indices of the chosen nodes is $n$ .

Can you find the maximum possible minimum difference between indices of the chosen nodes over all vertex covers?

The first line contains a single integer $t$ ( $1 \le t \le 10^4$ ) — the number of test cases.

The first line of each test case contains two integers $n$ and $m$ ( $1 \le n \le 10^{5}, 1 \le m \le 2 \cdot 10^{5}$ ) — the number of nodes and the number of edges.

The $i$ -th of the following $m$ lines in the test case contains two positive integers $u_i$ and $v_i$ ( $1 \le u_i,v_i \le n$ ), meaning that there exists an edge between them in the graph.

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^{5}$ .

It is guaranteed that the sum of $m$ over all test cases does not exceed $2 \cdot 10^{5}$ .

For each test case, print the maximum minimum difference between indices of the chosen nodes over all vertex covers.

In the first test case, we can install cameras at nodes $1$ , $3$ , and $7$ , so the answer is $2$ .

In the second test case, we can install only one camera at node $1$ , so the answer is $3$ .