CF1920B.Summation Game

普及/提高-

通过率:0%

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题目描述

Alice and Bob are playing a game. They have an array a1,a2,,ana_1, a_2,\ldots,a_n . The game consists of two steps:

  • First, Alice will remove at most kk elements from the array.
  • Second, Bob will multiply at most xx elements of the array by 1-1 .

Alice wants to maximize the sum of elements of the array while Bob wants to minimize it. Find the sum of elements of the array after the game if both players play optimally.

输入格式

Each test consists of multiple test cases. The first line contains a single integer tt ( 1t1041 \leq t \leq 10^4 ) — the number of test cases. The description of the test cases follows.

The first line of each test case contains three integers nn , kk , and xx ( 1n21051 \leq n \leq 2 \cdot 10^5 , 1x,kn1 \leq x,k \leq n ) — the number of elements in the array, the limit on the number of elements of the array that Alice can remove, and the limit on the number of elements of the array that Bob can multiply 1-1 to.

The second line of each test case contains nn integers a1,a2,,ana_1, a_2,\ldots, a_n ( 1ai10001 \leq a_i \leq 1000 ) — the elements of the array.

It is guaranteed that the sum of nn over all test cases does not exceed 21052 \cdot 10^5 .

输出格式

For each test case, output a single integer — the sum of elements of the array after the game if both players play optimally.

输入输出样例

  • 输入#1

    8
    1 1 1
    1
    4 1 1
    3 1 2 4
    6 6 3
    1 4 3 2 5 6
    6 6 1
    3 7 3 3 32 15
    8 5 3
    5 5 3 3 3 2 9 9
    10 6 4
    1 8 2 9 3 3 4 5 3 200
    2 2 1
    4 3
    2 1 2
    1 3

    输出#1

    0
    2
    0
    3
    -5
    -9
    0
    -1

说明/提示

In the first test case, it is optimal for Alice to remove the only element of the array. Then, the sum of elements of the array is 00 after the game is over.

In the second test case, it is optimal for Alice to not remove any elements. Bob will then multiply 44 by 1-1 . So the final sum of elements of the array is 3+1+24=23+1+2-4=2 .

In the fifth test case, it is optimal for Alice to remove 9,99, 9 . Bob will then multiply 5,5,35, 5, 3 by 1-1 . So the final sum of elements of the array is 553+3+3+2=5-5-5-3+3+3+2=-5 .

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