CF1919H.Tree Diameter

普及/提高-

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题目描述

There is a hidden tree with nn vertices. The n1n-1 edges of the tree are numbered from 11 to n1n-1 . You can ask the following queries of two types:

  1. Give the grader an array aa with n1n - 1 positive integers. For each edge from 11 to n1n - 1 , the weight of edge ii is set to aia_i . Then, the grader will return the length of the diameter ^\dagger .
  2. Give the grader two indices 1a,bn11 \le a, b \le n - 1 . The grader will return the number of edges between edges aa and bb . In other words, if edge aa connects uau_a and vav_a while edge bb connects ubu_b and vbv_b , the grader will return min(dist(ua,ub),dist(va,ub),dist(ua,vb),dist(va,vb))\min(\text{dist}(u_a, u_b), \text{dist}(v_a, u_b), \text{dist}(u_a, v_b), \text{dist}(v_a, v_b)) , where dist(u,v)\text{dist}(u, v) represents the number of edges on the path between vertices uu and vv .

Find any tree isomorphic ^\ddagger to the hidden tree after at most nn queries of type 1 and nn queries of type 2 in any order.

^\dagger The distance between two vertices is the sum of the weights on the unique simple path that connects them. The diameter is the largest of all those distances.

^\ddagger Two trees, consisting of nn vertices each, are called isomorphic if there exists a permutation pp containing integers from 11 to nn such that edge ( uu , vv ) is present in the first tree if and only if the edge ( pup_u , pvp_v ) is present in the second tree.

输入格式

The first and only line of input contains a single integer nn ( 3n10003 \le n \le 1000 ) — the number of vertices in the tree.

输出格式

Begin the interaction by reading nn .

You are allowed to make queries in the following way:

  1. " ?1a1a2an1\mathtt{?}\,1\,a_1\,a_2 \ldots a_{n-1} " ( 1ai1091 \le a_i \le 10^9 ). Then, you should read an integer kk which represents the length of the diameter. You are only allowed to ask this query at most nn times.
  2. " ?2ab\mathtt{?}\,2\,a\,b " ( 1a,bn11 \le a, b \le n - 1 ). Then, you should read an integer kk which represents the number of edges between edges aa and bb . You are only allowed to ask this query at most nn times.

In case your query is invalid. the program will terminate immediately and you will receive Wrong answer verdict.

To give the final answer, print "!" on a single line, followed by n1n - 1 lines where line ii contains " uiviu_i\,v_i " ( 1ui,vin1 \le u_i, v_i \le n ) which represents that for each ii from 11 to n1n-1 , there is an edge between uiu_i and viv_i .

After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:

  • fflush(stdout) or cout.flush() in C++;
  • System.out.flush() in Java;
  • flush(output) in Pascal;
  • stdout.flush() in Python;
  • see documentation for other languages.

Hacks

The first line contains a single integer nn ( 3n10003 \le n \le 1000 ) — the number of vertices in the tree.

The next n1n - 1 lines contain two integers each ui,viu_i, v_i ( 1ui,vin1 \le u_i, v_i \le n ) — the edges of the tree.

输入输出样例

  • 输入#1

    5
    
    3
    
    1
    
    9
    
    0

    输出#1

    ? 1 1 1 1 1
    
    ? 2 1 3
    
    ? 1 4 3 2 1
    
    ? 2 4 2
    
    !
    3 1
    4 2
    1 2
    2 5

说明/提示

The hidden tree in the example is shown above. The number on the vertices represents the vertex number while the number on the edges represents the edge number.

In the first query, all the edges are set to weight 11 , so the diameter has length 33 as shown in the diagram.

In the second query, there is 11 edge between edges 11 and 33 .

In the third query, the diameter is 99 by taking edges 11 , 22 and 33 .

In the fourth query, there are no edges between edges 44 and 22 .

The answer given in the example is shown in the above diagram. Since it is isomorphic to the hidden tree, it is accepted as a correct answer. Note that the edges can be printed in any order.

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