CF1919A.Wallet Exchange

Alice and Bob are bored, so they decide to play a game with their wallets. Alice has $a$ coins in her wallet, while Bob has $b$ coins in his wallet.

Both players take turns playing, with Alice making the first move. In each turn, the player will perform the following steps in order:

1. Choose to exchange wallets with their opponent, or to keep their current wallets.
2. Remove $1$ coin from the player's current wallet. The current wallet cannot have $0$ coins before performing this step.

The player who cannot make a valid move on their turn loses. If both Alice and Bob play optimally, determine who will win the game.

Each test contains multiple test cases. The first line contains a single integer $t$ ( $1 \leq t \leq 1000$ ) — the number of test cases. The description of the test cases follows.

The first and only line of each test case contains two integers $a$ and $b$ ( $1 \le a, b \le 10^9$ ) — the number of coins in Alice's and Bob's wallets, respectively.

For each test case, output "Alice" if Alice will win the game, and "Bob" if Bob will win the game.

In the first test case, an example of the game is shown below:

• Alice chooses to not swap wallets with Bob in step 1 of her move. Now, $a=0$ and $b=1$ .
• Since Alice's wallet is empty, Bob must choose to not swap their wallets in step 1 of his move. Now, $a=0$ and $b=0$ .
• Since both Alice's and Bob's wallets are empty, Alice is unable to make a move. Hence, Bob wins.

In the second test case, an example of the game is shown below:

• Alice chooses to swap wallets with Bob in step 1 of her move. Now, $a=3$ and $b=1$ .
• Bob chooses to swap wallets with Alice in step 1 of his move. Now, $a=1$ and $b=2$ .
• Alice chooses to not swap wallets with Bob in step 1 of her move. Now, $a=0$ and $b=2$ .
• Since Alice's wallet is empty, Bob can only choose to not swap wallets with Alice in step 1 of his move. Now, $a=0$ and $b=1$ .
• Since Alice's wallet is empty, Alice can only choose to swap wallets with Bob in step 1 of her move. Now, $a=0$ and $b=0$ .
• Since both Alice's wallet and Bob's wallet are empty, Bob is unable to make a move. Hence, Alice wins.